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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4. 	char a, b, c;
  5. 	printf("Size of datatype is %zu byte(s)\n", sizeof(char));
  6.  
  7. 	a = 118;		//      0 111 0110
  8. 	b = 25;			//      0 001 1001
  9. 	c = a + b;      //      1 000 1111
  10. 	printf("%d + %d = %d\n", a, b, c);
  11.  
  12. 	a = 118;		//      0 111 0110
  13. 	b = 25;			//      0 001 1001
  14. 	c = a * b;      // 1011 1 000 0110
  15. 	printf("%d * %d = %d\n", a, b, c);
  16.  
  17. 	return 0;
  18. }
  19.  
Success #stdin #stdout 0s 9416KB
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Standard input is empty
stdout
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Size of datatype is 1 byte(s)
118 + 25 = -113
118 * 25 = -122
https://ideone.com/3WBeQ3
language:
C (gcc 8.3)
created:
6 years ago
visibility:
secret

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