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  1. #include <stdio.h>
  2. #include<math.h>
  3.  
  4.  
  5. 	float distance(int n1,int m1,int n2,int m2){
  6. 		float d=0;float sum=0;
  7. 		d =sqrt(pow(m2-m1,2)+pow(n2-n1,2));
  8. 		sum+=d;
  9. 		printf("%.2f",sum);
  10. 		return sum;
  11. 	}
  12. 	int main(void) {
  13. int t,n,i,j;float sum=0;
  14. scanf("%d",&t);
  15. while(t--){
  16. 	scanf("%d",&n);
  17. 	int r=0,s=0,a=0,b=0;
  18. 	int x[100002],y[100002],p[100002],q[100002],min[100002],max[100002];
  19. 	for(i=0;i<n;i++){
  20. 	scanf("%d %d",&x[i],&y[i]);}
  21.  
  22. 	for(j=0;j<10001;j++){
  23. 		for(i=0;i<n;i++){
  24. 			if(j==x[i]){
  25. 				p[r++]=x[i];q[s++]=y[i];
  26. 			}
  27. 			}}
  28. 			for(i=0,j=i+1;i<n&&j<n;i++,j++){
  29. 				if(p[i]==p[j]){
  30. 					if(q[i]>q[j]){min[a++]=p[i]; max[b++]=q[i];}
  31. 					else{min[a++]=p[i]; max[b++]=q[j];}
  32. 				}
  33. 				else{min[a++]=p[i]; max[b++]=q[i];}
  34. 			}
  35.  
  36. 	for(i=0;i<n;i++){
  37. 		distance(min[i],max[i],min[i+1],max[i+1]);
  38. 	}
  39.  
  40. 	printf("%.2f\n",sum);
  41.  
  42.  
  43. }
  44.  
  45. }
  46.  
Success #stdin #stdout 0s 4512KB
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https://ideone.com/2YlS9J
language:
C (gcc 8.3)
created:
11 years ago
visibility:
public

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